News
We can use perpendicular gradients to find the value of \(m\), then use the coordinates of P to find the value of \(c\) in the equation. Find the equation of the tangent to the circle \(x^2 + y^2 ...
6d
Interesting Engineering on MSN380-year-old Descartes circle problem finally solved with help from physicsUsing advanced mathematical tools inspired by physics, the team has derived a general equation for any number of tangent ...
We can use perpendicular gradients to find the value of \(m\), then use the coordinates of P to find the value of \(c\) in the equation. Find the equation of the tangent to the circle \(x^2 + y^2 ...
Some results have been hidden because they may be inaccessible to you
Show inaccessible results